Question

la funcion es g(x)=3xala4 -4x+1 hallar g(-1/2)

Answer 1

g(x)=3x⁴-4x+1

Hallar

g(-1/2) = 3(-1/2)⁴-4(-1/2)+1
g(-1/2) = 3(1/16)+2+1
g(-1/2) = 3/16+3
g(-1/2) = (3+48)/16 =51/16

Espero te sirva

Saludos