Question

F(x)=(z2-3z+1)/(2z2+5)z─>0

Answer 1

F(z) = (z²-3z+1)/(2z²+5)
lim z->0

Aquí debes reemplazar 0 en z y ver el limite

F(0) = (0²-3(0)+1)/(2(0)²+5)
F(0) = 1/5

Espero te sirva