Question

1 + tan²β ÷ Tan² β !!

Answer 1

[1+tg²(x)] / tg²(x)

1/tg²(x) + tg²(x)/tg²(x)

ctg²(x) + 1

cos²(x)/sen²(x) + 1

[cos²(x)+sen²(x)] / sen²(x)

Cambiamos cos²(x)+sen²(x) por 1

1/sen²(x)

csc²(x)