Question

Resolver con procedimiento plis ecuacion diferencial

2z´ - xz = 0

Answer 1

$2z' - xz = 0 \\ 2\frac{dz}{dx}-xz=0\\ 2\frac{dz}{dx}=xz\\ \frac{2}{z}\ dz=x\, dx\\ \int\frac{2}{z}\ dz=\int x\,dx\\ 2\ln z=\frac{x^2}{2}+C\\ \ln z=\frac{x^2}{4}+\frac{C}{2}\\ z=e^{\frac{x^2}{4}+\frac{C}{2}}\\ z=C_1e^{\frac{x^2}{4}}$