Question

calcular la composicion centesimal de
a) NaNO3
b) C4H10
c) C2H60

Answer 1

A) NANO3  85gr/mol 
% NA  23/85*100 = 27.05%
%N 14/85*100 =  16.47%
%O 16*3/85*100 = 56.47 %

B) C4H10  58 gr/mol
% C 12*4/58*100 = 82.75%
%H 1*10 /58*100 =17.241%

C) C2H6O 46gr/mol
%C 12*2/ 46*100= 52.17%
%H 1*6/46 *100 = 13.04%
%O 16/46  *100 =34.78%