Question

Halle el volumen de un gas que esta a una presion de 6840 mmHg a una temperatura de 258 °F y contiene 2 moles

con procedimiento

gracias

Answer 1

V = ?

P = 6840 / 760 = 9 atm

n = 2 mol

T = 258 ºF (transformar a K)

ºC = ºF - 32 / 1.8

ºC =  258 - 32 / 1.8 = 125.56 ºC

K = ºC + 273

K =  125.56 + 273 = 398.56 K

R = 0.0821 ( L atm / mol K)

V  P  = n R T

V = 2 mol  x  0.0821 ( L atm / mol K)  x  398.56 K
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                               9 atm

V = 7.27 L