El hidrógeno se puede obtener por la reacción de hidruro de calcio y el agua, segun esta reaccion:CaH2+2H2O------>Ca(OH)2+ 2H2A) ¿cuantos gramos de H2 se pueden producir a partir de 140 ramos de hidruro?B) ¿Cuantos gramos de hidroxido se producen a partir de este hidruro?C) ¿Cuanto hidruro se requiere para producir 300 gramos de hidroxido de calcio? ¿Cuántos gramos de agua se requieren para producir 30 gramos de hidrógeno? Ayuda, por favor
Respuestas
Respuesta dada por:
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a)
Mm CaH2 = 42 g/mol
H2 = 2 g/mol
g H2 = 140 CaH2 x 1 mol CaH2 x 2 mol CH2 x 2 g H2
`````````````````` ```````````````````` ``````````
42 g CaH2 1 mol CaH2 1 mol H2
g = 13.33 g de H2
b.
Mm Ca(OH)2 = 74 g/mol
g Ca(OH)2 = 140 CaH2 x 1 mol CaH2 x 1 mol Ca(OH)2 x 74 g Ca(OH)2
`````````````````` `````````````````` ````````````````````
42 g CaH2 1 mol CaH2 1 mol Ca(OH)2
g = 246.66 g CaOH)2
C.
g CaH2 = 300 g Ca(OH)2 x 1 mol Ca)OH)2 x 1mol CaH2 x 42 g Ca(OH)2
`````````````````````` ````````````````` ````````````````````
74 g Ca(OH)2 1 mol Ca(OH)2 1 mol CaH2
g = 170.27 g de CaH2
D.
Mm H2O = 18 g/mol
g H2O = 30 g H2 x 1 mol H2 x 2 mol H2O x 18 g H2O
`````````````` ```````````````` ``````````````
2 g H2 2 mol H2 1 mol H2O
g = 270 de H2O
Mm CaH2 = 42 g/mol
H2 = 2 g/mol
g H2 = 140 CaH2 x 1 mol CaH2 x 2 mol CH2 x 2 g H2
`````````````````` ```````````````````` ``````````
42 g CaH2 1 mol CaH2 1 mol H2
g = 13.33 g de H2
b.
Mm Ca(OH)2 = 74 g/mol
g Ca(OH)2 = 140 CaH2 x 1 mol CaH2 x 1 mol Ca(OH)2 x 74 g Ca(OH)2
`````````````````` `````````````````` ````````````````````
42 g CaH2 1 mol CaH2 1 mol Ca(OH)2
g = 246.66 g CaOH)2
C.
g CaH2 = 300 g Ca(OH)2 x 1 mol Ca)OH)2 x 1mol CaH2 x 42 g Ca(OH)2
`````````````````````` ````````````````` ````````````````````
74 g Ca(OH)2 1 mol Ca(OH)2 1 mol CaH2
g = 170.27 g de CaH2
D.
Mm H2O = 18 g/mol
g H2O = 30 g H2 x 1 mol H2 x 2 mol H2O x 18 g H2O
`````````````` ```````````````` ``````````````
2 g H2 2 mol H2 1 mol H2O
g = 270 de H2O
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