Question

que presión ejercen 0.46 g de O2 a la temperatura de 42°C, ocupando un volumen de 15ml

Answer 1

LEY DE LOS GASES IDEALES: V P = n R T

V = 15 mL / 1000 = 0.015 L
P= ?
m = 0.46 g de O2
Mm O2 = 32 g/mol
R = 0.0821 (L a tm / mol K)
T = 42 ºC + 273 = 315 K

1. CALCULAR  n (moles)
n = masa/Mm
n = 0.46 g / 32 g/mol
n = 0.0144 mol

2. calcula P

P = 0.0144 mol x 0.0821 (L atm/ mol K) x  315 K
       ``````````````````````````````````````````````````````````````
                                0.015 L

P = 24.82 atm.