Question

2. si f (x)= x 2 - 3x + 2 determinar

a) F(1/2)

b) F(-1)

C) F (1/a)

d) F(x+h)

Answer 1

reemplazamos cada variable en la funcion dada
f(x)=x2-3x+2

f(1/2)=(1/2)´2-3(1/2)+2
f(1/2)=1/4-3/2+2
f(1/2)=(4-6+8)/4
f(1/2)=6/4=3/2

f(-1)=(-1)´2-3(-1)+2
f(-1)=1+3+2=6
f(-1)=6

f(1/a)=(1/a)´2-3(1/a)+2
f(1/a)=1/(a¨2)-3/a+2
f(1/a)=(1-3a+2a´2)/a¨2
f(1/a)=(2a¨2-3a+1)/a¨2

f(x+h)=(x+h)¨2-3(x+h)+2
f(x+h)=x¨2+2xh+h¨2-3x-3h+2

saludos