Question

(x4-t)3y2-(x4-t)(y-1)+(x4-t)(y-2)

Answer 1

(x4-t)3y2-(x4-t)(y-1)+(x4-t)(y-2)

Primero arreglamos
(4x-t)6y - (4x -t)(y-1) + (4x-t)(y-2)

Multiplicamos
(24xy -6ty) - ( (4xy - ty) + (-4x +t) ) + ( (4xy -ty) + (-8x + 2t) )

Re-Arreglamos
24xy - 6ty - 4xy + ty +4x -t +4xy -ty - 8x +2t

Sumamos
xy(24-4+4) + ty(-6+1-1) +x(4-8) +t (-1 +2)
xy(24) +ty(-6) +x(-4) + t(1)
24xy -6ty -4x +t

reordenamos
24xy -4x -6ty +t

factor comun
4x(6y-1) - t(6y +1)

Asi queda, creo, si no me equivoqué