Question

el area de un rombo es de 169m2, si la diagonal mayor mide el doble de la menor,¿cuánto mide cada uno?

Answer 1

Area del rombo = $\frac{D.d}{2}$

Diagonal  mayor = 2x
diagonal menor = x

$169 m ^{2} = \frac{2x.x}{2}$

$169 m ^{2} = x^{2}$

$\sqrt{169m^{2} } = \sqrt{x^{2} }$

13 m = x  = Diagonal menor

Diagonal mayor = 2x = 2(13) = 26 m