Question

8^ -2/3 con procedimiento

Answer 1

$8^{- \frac{2}{3} } = \frac{1}{ 8^{ \frac{2}{3} } } = \frac{1}{ \sqrt[3]{8^{2} } } = \frac{1}{ \sqrt[3]{ (2^{3} ) ^{2} } } = \frac{1}{ \sqrt[3]{2^{6} } } = \frac{1}{2^{2} } = \frac{1}{4}$