Question

cuantos multiplos de 5 hay entre 9 y 308 , ayuda porfa

Answer 1

La serie de múltiplos de 5 forman una PA con razón 5
Término general
                             an = a1 + (n - 1).r

En el caso en estudio
                                    a1 = 10
                                    an = 305
                                      n = ??
                                       r = 5
                                                   305 = 10 + (n - 1).5
                           resolviendo
                                       (305 - 10)/5 = n - 1
                                                     59 = n -1
                                                       n = 59 + 1
                                                          = 60

                                                       HAY 60 MÚLTIPLOS