Question

Dada la función f(x)=2x^2-3x,
Hallar
f(-2)=
f(0)=
f(a+1)=

Answer 1

f(x)=2x²-3x

f(-2)=2x²-3x
f(-2)=2(-2)²-3(-2)
f(-2)=2(4)+6
f(-2)=8+6
f(-2)=14

f(0)=2x²-3x
f(0)=2(0)²-3(0)
f(0)=2(0)-0
f(0)=0

f(a+1)=2x²-3x
f(a+1)=2(a+1)²-3(a+1)
f(a+1)=2(a²+2a+1)-3a-3
f(a+1)=2a²+4a+2-3a-3
f(a+1)=2a²+a-1

Saludos!!