Question

1.5 litros de NaHCO3 0.2M

Answer 1

Mm NaHCO3 = 84 g/mol

M = mol soluto / V(L)

despejar mol

mol = 0.2 mol/L  ·  1.5 L

mol = 0.30

masa = mol x Mm

masa = 0.30 mol  ·  84 g/mol

masa = 25.2 g de NaHCO3