la formula empirica de un compuesto de ch si el peso molecular es de 130gr ¿cual es la formula verdadera?
Respuestas
Respuesta dada por:
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FE: CH
Mm DE LA FE
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
``````````````````````````````
Mm = 13 g/mol
n = M molar del compuesto
````````````````````````````````
M molar FE
n = 130 g/mol
````````````````
13 g/mol
n = 10
FM: (CH)n = (CH)10 = C10H10 (Ciclodecapentaeno)
Mm DE LA FE
C: 1 x 12 = 12 g/mol
H: 1 x 1 = 1 g/mol
``````````````````````````````
Mm = 13 g/mol
n = M molar del compuesto
````````````````````````````````
M molar FE
n = 130 g/mol
````````````````
13 g/mol
n = 10
FM: (CH)n = (CH)10 = C10H10 (Ciclodecapentaeno)
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