Question

CALCULOS COMBINADOS: {[(8:4+2)^3 ]- √(324∶ 3^2 )+16:8 }=
[(10∶2+1)]+ [(8-5) ∙ 2^2 ]^0=

Answer 1

{[(8÷4+2)^3]-√(324÷3^2)+16÷8}=
[(2+2)^3-√324÷9+16÷8]=
(4)^3-√36+2=
64-6+3=
61

[(10÷2+1)]+[(8-5)2^2]^0=
(5+1)+(1)=
6+1=
7