Question

201 a base 4 plis y tambien 111111 a base 2 al sistema decimal

Answer 1

$2\cdot4^2+0\cdot4^1+1\cdot4^0=32+0+1=33\\ 201_4=33_{10}\\\\ 1\cdot2^5+1\cdot2^4+1\cdot2^3+1\cdot 2^2+1\cdot2^1+1\cdot2^0=\\ =32+16+8+4+2+1=63\\ 111111_2=63_{10}$