Question

Que volumen ocuparan 3,5 moles de amoniaco a -13 °c y 4,9 atm



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Answer 1

P V = n  R T

V = ?
P = 4.9 atm
n = 3.5 moles
T = -13 + 273 = 260 K
R = 0.0821 (L atm / mol  K)

V = n  R  T
       ````````
           p

V = 3.5 moles x 0.0821 /L atm / mol K) x 260 K
     ``````````````````````````````````````````````````````````````
                                   4.9 atm

V = 15.25 Litros