Question

quien me ayuda con esto por fa..

Answer 1

A)
C: 60 g / 12 g/mol = 5 mol
H: 4.5 g/ 1 g/mol = 4.5 mol
O: 35.5 g/ 16 g/mol = 2.218

dividir

C: 5 mol / 2.218 mol = 2.25 X 4 = 9
H: 4.5 mol / 2.218 mol = 2 X 4 = 8
O: 2.218 ol / 2.218 mol = 1 x 4 = 4

FE: C9H8O4

Mm FE:
C:  9 X 12 =108 g/mol
H. 8 x 1 = 8 g/mol
O: 4 x 16 = 64 g/mol
````````````````````````````````
      Mm = 180 g/mol

n = 180 g/mol / 180 g/mol
n = 1

FM= (C9H8O4)1 = C9H8O4

B)

Na: 19.3 g/ 23 g/mol = 0.839 mol
S: 26.9 g / 32 g/mol = 0.840 mol
O: 53.8 g/ 16 g/mol = 3.363 mol

dividir

Na: 0.839 mol / 0.839 mol = 1
 S:  0.840 mol / 0.839 mol = 1
 O: 3.363 mol / 0.0839 mol = 4

FE: NaSO4

Mm de la FE
Na: 1 x 23 = 23 g/mol
 S: 1 x 32 = 32 g/mol
 O: 4 x 16 = 64 g/mol
````````````````````````````
         Mn = 89 g/mol

n = 238 g/mol / 89 g/mol
n = 2

FM: (NaSO4)2 = Na2S2O8

3)
 ₊₂  ₊₆  ₋₂
Ca S O4

 ₊₂     ₊₃  ₋₂
Ca3(B O3)2

₊₁   ₊₃  ₋₂
H3AsO3

 ₊₁   ₊₅  ₋₂
Na3P O4