Respuestas
Respuesta dada por:
8
[(m+5)^2-(m-5)^2)]/10m=
[(m^2+10m+25)-(m^2-10m+25)]/10m=
(m^2+10m+25-m^2+10m-25)/10m=
[(m^2-m^2)+(10m+10m)+(25-25)]/10m=
[(0)+(20m)+(0)]/10m=
20m/10m=
2
[(m^2+10m+25)-(m^2-10m+25)]/10m=
(m^2+10m+25-m^2+10m-25)/10m=
[(m^2-m^2)+(10m+10m)+(25-25)]/10m=
[(0)+(20m)+(0)]/10m=
20m/10m=
2
gato23axossg65:
asuuuu pero tanto seguro que esta bien
Respuesta dada por:
4
La identidad de Legendre.
![(a + b)^{2}+ (a - b)^{2}= 2( a^{2} + b^{2}) (a + b)^{2}+ (a - b)^{2}= 2( a^{2} + b^{2})](https://tex.z-dn.net/?f=%28a+%2B+b%29%5E%7B2%7D%2B+%28a+-+b%29%5E%7B2%7D%3D+2%28+a%5E%7B2%7D+%2B+b%5E%7B2%7D%29+)
![(a + b)^{2} - (a - b)^{2}= 4ab (a + b)^{2} - (a - b)^{2}= 4ab](https://tex.z-dn.net/?f=%28a+%2B+b%29%5E%7B2%7D+-+%28a+-+b%29%5E%7B2%7D%3D+4ab)
![=============================== ===============================](https://tex.z-dn.net/?f=%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D%3D)
Usamos el segundo método.
![\frac{(m+5)^{2}-(m-5)^{2}}{10m} \frac{(m+5)^{2}-(m-5)^{2}}{10m}](https://tex.z-dn.net/?f=+%5Cfrac%7B%28m%2B5%29%5E%7B2%7D-%28m-5%29%5E%7B2%7D%7D%7B10m%7D+)
![\frac{4(m)(5)}{10m} \frac{4(m)(5)}{10m}](https://tex.z-dn.net/?f=+%5Cfrac%7B4%28m%29%285%29%7D%7B10m%7D+)
![\frac{20m}{10m} \frac{20m}{10m}](https://tex.z-dn.net/?f=+%5Cfrac%7B20m%7D%7B10m%7D+)
<== respuesta.
Usamos el segundo método.
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