Question

AYUDENME URGENTE PORFAVOR''''''''''' OJO:DEBEN SACAR MINIMO COMUN MULTIPLO

Answer 1

$\frac{5x+1}{4} = \frac{4x-3}{3} \\ \\ 12( \frac{5x+1}{4})=12(\frac{4x-3}{3} ) \\ \\ 3(5x+1)=4(4x-3) \\ \\ 15x+3=16x-12 \\ \\ 15x-16x=-12-3 \\ \\ -x=-15 \\ \\ x=15 \\ \\ \\ \frac{2x-1}{3}- \frac{4x}{5} =x-6 \\ \\ 15( \frac{2x-1}{3})-15(\frac{4x}{5} )=15(x-6) \\ \\ 5(2x-1)-3(4x)=15x-90 \\ \\ 10x-5-12x=15x-90 \\ \\ -2x-5=15x-90 \\ \\ -2x-15x=-90+5 \\ \\ -17x=-85 \\ \\ x= \frac{-85}{-17} \\ \\ x=5$

$\frac{x+2}{5} - \frac{x+1}{2}=2x-7 \\ \\ 10( \frac{x+2}{5})-10( \frac{x+1}{2})=10(2x+7) \\ \\ 2(x+2)-5(x+1)=20x+70 \\ \\ 2x+4-5x-5=20x+70 \\ \\ -3x-1=20x+70 \\ \\ -3x-20x=70+1 \\ \\ -23x=71 \\ \\ x=- \frac{71}{23}$