Question

 ayuda a resolver 4logx=2 log x+log4+2

Answer 1

4㏒x = 2㏒x + ㏒4 +2
2㏒x = ㏒4 + 2
⊕ 2㏒x = ㏒$x^{2}$
㏒$x^{2}$ - ㏒4 =2
㏒($\frac{ x^{2} }{4}$) = 2
$10^{2}$ = $\frac{ x^{2} }{4}$
$x^{2}$ = 400
$x = 20$