Question

determina los 6 primeros terminos de una progresion geometrica si los dos primeros terminos son 2 y 5

Answer 1

$an = a1.q ^{n-1}$
$q= \frac{a(n)}{a(n-1)}$

a1 = 5
a2 = 3
  q = 3/5
  
          a3 = (3/5)^2 = 9/25
          a4 = (3/5)^3 = 27/125
          a5 = (3/5)^4 = 81/625
          a6 = (3/5)^5 = 243/3125

A = 5, 3, 9/25, 27/125, 81/625, 243/3125