Question

calcular la normalidad de 20.5 g de carbonato sodico en 0.5 litros de solucion

Answer 1

Mm Na2CO3 = 105.9  g/mol

Peq = 105.9 g/mol /2 = 52.95 g/eq.

eq. = masa/Peq.

eq. = 20.5 g/ 52.95g/eq

eq. = 0.387

N = eq. / V(L)

N = 0.387 eq. / 0.5 L

N = 0.774 eq/L