Question

calcular la velocidad angular de cada aguja del reloj

Answer 1

Horero
El horero recorre 12h en un vuelta

t = 12×60min/1h×60s/1min = 43200s
ω =?
θ = 2pi
θ = ω×t
ω = θ /t
ω = 2pi/43200s
ω = 1.45×10^-4 rad/s

Minutero
El. Minutero tarda 60min en dar una vuelta
t = 60min ×60s/1min = 3600
θ = 2PI
ω =?
ω = θ /t
ω = 2pi/3600S
ω = 0.0017 rad/s

Segundero
t = 60s
θ = 2pi
ω =?
ω = θ /t
ω = 2pi/60s
ω = 0.105 rad/s