Question

si f(θ)=SEN2θ+cosθ, hallar f(0), f(1/2π),f(π)

Answer 1

t = theta

f( t ) = Sen( 2t ) + Cos( t )

f(0) = Sen( 2 * 0 ) + Cos(0)
f(0) = Sen(0) + Cos(0) = 0 + 1 = 1

f( 1/2 π ) = Sen( 2(1/2) π ) + Cos( 1/2π )
f( 1/2 π ) = Sen( π ) + Cos( π/2 )
f( 1/2 π ) = 0 + 0 = 0

f( π ) = Sen( 2 * π ) + Cos( π )
f( π ) = 0 + ( - 1 ) = - 1

Verifica en las gráficas de seno y coseno

Espero haberte ayudado, saludos!