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Sea 2x+1. 2x+3, 2x+5 los numeros impares consecutivos
2x+1+ 2x+3 + 2x+5 = 111
6x + 9 = 111
6x = 111-9
6x = 102
x = 102/6
x = 17
2x+1 = 2(17)+1 = 34+1 = 35
2x+1 = 2(17)+3 = 34+3 = 37
2x+1 = 2(17)+5 = 34+5 = 39
2x+1+ 2x+3 + 2x+5 = 111
6x + 9 = 111
6x = 111-9
6x = 102
x = 102/6
x = 17
2x+1 = 2(17)+1 = 34+1 = 35
2x+1 = 2(17)+3 = 34+3 = 37
2x+1 = 2(17)+5 = 34+5 = 39
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