Question

Factorización de operaciones

a(n+2)+n+2   
x(a+1)-a-1    
x(2a+b+c)-2a-b-c

Answer 1

a(n+2)+n+2=
a(n+2)+1(n+2)=
(n+2)(a+1)

x(a+1)-a-1=
x(a+1)-1(a+1)=
(a+1)(x+1)

x(2a+b+c)-2a-b-c=
x(2a+b+c)-1(2a+b+c)=
(2a+b+c)(x-1)