Question

SUMAS

1)(3x4−2x6+x3−x+5)+(x6−3x2+4x−1)=

2)(2x+3x3−5x3+2x4+5x−1)+(8x3−x4+5x2−9x3)=

3)(2x5−3x4+x3−8x2+2x−7)+(−4+2x2−6x4+x5)=

RESTAS

4)(4x4−3x3+5x4+8x3−4x2+3)−(−5x3−4x4+7+2x2−5x)=

5)(2x7+x5−4x+6x3−2)−(9x3−12x5+2x7−3x3)=

6)(11x2−4x4+8x−9)−(23x4−5x2−6−5x)=

Answer 1

De la primera es 24 intentaré las otras