Question

Hallar el valor de x
Incluyendo Cálculos Auxiliares por favor

Answer 1

$\frac{4-6x}{10}-\frac{x-1}{3}=1\\\frac{3(4-6x)}{3(10)}-\frac{10(x-1)}{10(3)}=1\\3(4-6x)-10(x-1)=30\\12-18x-10x+10=30\\-28x=30-12-10\\-28x=8\\x=-\frac{2}{7}\\\\\\\frac{2x-1}{3}+\frac{3x-5}{2}=\frac{3}{4}x-1\\\frac{2(2x-1)}{2(3)}+\frac{3(3x-5)}{3(2)}=\frac{3}{4}x-1\\\frac{4x-2}{6}+\frac{9x-15}{6}=\frac{3}{4}x-1\\4x-2+9x-15=\frac{6(3)}{4}x-1(6)\\13x-17=\frac{9}{2}x-6\\13x-\frac{9}{2}x=17-6\\\frac{26x-9x}{2}=11\\17x=22\\x=\frac{22}{17}$