Question

(1/8a - 3/4b) elevado a la 2

Answer 1

$( \dfrac{1}{8}a- \dfrac{3}{4} b)^2=( \dfrac{a}{8}- \dfrac{3b}{4} )^2\quad \quad \quad(a-b)^2=a^2-2ab+b^2 \\ \\ \\ =( \dfrac{a}{8} )^2-2( \dfrac{a}{8})( \dfrac{3b}{4} )+( \dfrac{3b}{4} )^2 \\ \\ \\ = \boxed{\bf \dfrac{a^2}{64} - \dfrac{6ab}{32} + \dfrac{9b^2}{16} }\to Respuesta$

Saludos desde Venezuela

Answer 2

$( \frac{1}{8} a- \frac{3}{4} b)^2= \\ \\ ( \frac{1}{8} a- \frac{3}{4} b)( \frac{1}{8} a- \frac{3}{4} b)= \\ \\ \frac{1}{64} a^2- \frac{3}{32} ab- \frac{3}{32} ab+ \frac{9}{16} b^2= \\ \\ \frac{1}{64} a^2- \frac{3}{16} ab+ \frac{9}{16} b^2$