Question

2. Halla "a+b+c", si: (x+3)(2x–5) ≡ ax 2 +b+cx

Answer 1

(x+3)(2x-5)=2x²-5x+6x-15
= 2x²+ x - 15
=2x² -15 +x

entonces a=2, b=-15 y c=1
a+b+c=2+(-15)+1
=-12

Saludos.