Question

log √3x+1 + log 5 = 1+log√2x-3

Answer 1

log(√3x+1)(5)=log(10)(√2x-3)
5(√3x+1)=10(√2x-3)
√3x +1=2√2x-3
elevalo al cuadrado
3x+1=4(2x-3)
13=5x
x=13/5