Question

9+3·{32÷8+4·[2·(4÷4+1)]}-2 porros ayudenme con la operacion

Answer 1

9+3·{32÷8+4·[2·(4÷4+1)]}-2=
9+3·{4+4·[2·(1+1)]}-2=
9+3·{8·[2·(2)]}-2=
9+3·{8·[4]}-2=
9+3·{32}-2=
9+96-2=
103