Question

calcula la posicion porcentual de los siguientes compuestos Ca3(po4)2 H3po4 urgeee

Answer 1

Ca3(PO4)2

Ca: 3 x 40 = 120 g/mol
 P: 2 x 31 = 62 g/mol
 O: 8 x 16 = 128 g/mol
````````````````````````````````
           Mm = 310 g/mol

CALCIO
310 g ---- 100 %
120 g -----  x
x = 38.71 % de Ca

Fósforo
310 g ---- 100 %
   62 g -----  x
x = 20 % de P

OXIGENO

 310 g ---- 100 %
 128 g -----  x
x = 41.29 % de O

H3PO4

H: 3 x 1 = 3 g/mol
P: 1 x 31 = 31 g/mol
O:  4 x 16 =64 g/mol
````````````````````````````
         Mm = 98 g/mol

H:
98 g ----  100%
 3 g -----      x
x = 3.06 % H

P:
98 g ----  100%
31 g -----      x
x = 31.63  % P

O.
98 g ----  100%
 64 g -----      x
x = 65.30 % O