Question

2^4 + 4^2 ÷ 2^3*√25 +7

Answer 1

$\dfrac{2^4+4^2}{2^3* \sqrt{25}+7 } = \dfrac{16+16}{8*5+7} = \dfrac{32}{40+7} = \boxed{\dfrac{32}{47} }==\ \textgreater \ Respuesta$

Recordemos que:   4² = 16
2⁴ = 16
√25 = 5
2³ = 8

Saludos desde Venezuela