Question

polinomios:

P(3x-1)=6x-10
p(f(x)+4)=5x+7
hallar F(-1/5)

Answer 1

P(3x-1)=6x-10
P(3x-1)=2(3x-1) - 8 **verifica: 6x-2-8 =6x-10
→ P(x)= 2x-8

P(f(x)+4)=5x+7
2(f(x)+4)-8=5x+7
2(f(x))+8-8=5x+7
2(f(x))=5x+7
f(x)=(5x+7)/2

→ f(-1/5) = [(-1/5)+7]/2
= (34/5)/2 = 34/10 = 17/5