Question

Calcular el PH y POH de una solución cuya concentración de protones es de 10 -9 Molar.

Answer 1

[H⁺] = 10⁻⁹ M

pH = -log [H⁺]

pH = - log (10⁻⁹)

pH = -(-8) = 8

pH + pOH = 14

pOH = 14 - pH

pOH = 14 - 8 = 6