Question

Calcula el valor de (x):
Problema 1
x²+(x+2)²=580

Answer 1

$x^2+(x+2)^2=580\\ x^2+x^2+4x+4=580\\ 2x^2+4x-576=0\\ x^2+2x-288=0\\ \Delta=2^2-4\cdot1\cdot(-288)=4+1152=1156\\ \sqrt{\Delta}=\sqrt{1156}=34\\ x_1=\frac{-2-34}{2\cdot1}=\frac{-36}{2}=-18\\ x_2=\frac{-2+34}{2\cdot1}=\frac{32}{2}=16$

Answer 2

x²+(x+2)²=580
x²+x²+4x+4=580
2x²+4x+4-580=0
x²+2x-288
(x+18) (x-16)
x+18=0
x= -18
x-16=0
x=16