Question

ecuaciones radicales √ 4x-11 = 7 √2x -29.

Answer 1

$\sqrt{4x-11} = 7\sqrt{2x-29} \\ (\sqrt{4x-11})^2=(7\sqrt{2x-29}) ^2 \\ 4x-11=49(2x-29) \\ -11=98x-4x-1421 \\ -11+1421=94x \\ 94x=1410 \\ x=1410/94 \\ x=15$