Question

Si y = x² - 4 cuanto vale Δy cuando x varia de 1 a 1.1?

Answer 1

y = x^2 - 4
dy/dx = 2x
dy = 2x*dx
dy = 2*1*(1.1-1)
dy = 2*0.1 = 0.2
Δy varia en 0.2

Answer 2

Δy = Δ f(x) = f(x) - f(x₀)

x₀= 1.0
x = 1.1

f(x₀)= -3.00
f(x) = -2.79

Luego, Δy= -2.79 - (-3.00) = 0.21