Question

derivada de un logaritmo natural , ayuda porfa

Answer 1

$d(Lnu)= \frac{1}{u}du \\ ej: Ln(x^2-2x+1) \\ d(Ln(x^2-2x+1) )= \frac{1}{x^2-2x+1} (2x-2)dx \\ d(Ln(x^2-2x+1) )= \frac{2x-2}{x^2-2x+1} dx$