Question

3(x-2)²(x+5) = 3(x+1)² (x-1) + 3

Answer 1

$3(x-2)^{2} (x+5)= 3(x+1)^{2}(x-1) + 3$

$3(x^{2}-4x + 4) (x+5)= 3(x^{2} + 2x+1)(x-1) + 3$

$(3x^{2}-12x + 12) (x+5)= (3x^{2} + 6x+3)(x-1) + 3$

$3x^{3}+ 15 x^{2} -12x^{2} - 60x + 12x+ 60= 3x^{3} - 3x^{2} + 6x^{2}-6x +3x -3$$+3$

$3x^{3}+ 3x^{2} - 48x + 60= 3x^{3} + 3x^{2} -3x$

$- 48x + 60= -3x$

$+ 60= -3x + 48x$

$+ 60= 45x$

$x = \frac{60}{45}$

$x = \frac{4}{3}$

Espero que te sirva, salu2!!!!