Como se hace esta ecuacion? 6 (x+1/8-2x-3/16)=3(3x/4-1/4)-3/8(3x-2)

Respuestas

Respuesta dada por: ValeriaRL
1
X in (-oo:+oo)

6*(X-(2*X)+1/8-(3/16)) = 3*((3/4)*X-(1/4))-((3/8)*(3*X-2)) // - 3*((3/4)*X-(1/4))-((3/8)*(3*X-2))

6*(X-(2*X)+1/8-(3/16))-(3*((3/4)*X-(1/4)))+(3/8)*(3*X-2) = 0

6*(X-2*X+1/8-3/16)-3*((3/4)*X-1/4)+(3/8)*(3*X-2) = 0

6*(-X-1/16)-3*(3/4*X-1/4)+3/8*(3*X-2) = 0

6*(-X-1/16)-3*(3/4*X-1/4)+3/8*(3*X-2) = 0

9/8*X-33/4*X-3/4+3/8 = 0

-57/8*X-3/8 = 0

-57/8*X-3/8 = 0

-57/8*X-3/8 = 0 // + 3/8

-57/8*X = 3/8 // : -57/8

X = 3/8/(-57/8)

X = -1/19

X = -1/19
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