Respuestas
Respuesta dada por:
3
acido fosforico: H3PO4
H: 3 x 1 = 3 g/mol
P:1 x 31 = 31 g/mol
O: 4 x 16 =64 g/mol
````````````````````````````
Mm =98 g/mol
H:
98 g --------- 100%
3 g --------- x
x = 3.06 % H
P:
98 g --------- 100%
31 g --------- x
x = 31.63 % P
O:
98 g --------- 100%
64 g --------- x
x = 65.30 % O
``````````````````````````````````````````````````````````````````````````
Ca(OH)2
Ca: 1 x 40 = 40 g/mol
O: 2 x 16 = 32 g/mol
H: 2 x 1 = 2 g/mol
``````````````````````````````
Mm =74 g /mol
Ca:
74 g ----- 100%
40 g ----- x
x = 54.05 % de Ca
O:
74 g ----- 100%
32 g ----- x
x = 43.24 % de O
H:
74 g ----- 100%
2 g ----- x
x = 2.70 % de H
H: 3 x 1 = 3 g/mol
P:1 x 31 = 31 g/mol
O: 4 x 16 =64 g/mol
````````````````````````````
Mm =98 g/mol
H:
98 g --------- 100%
3 g --------- x
x = 3.06 % H
P:
98 g --------- 100%
31 g --------- x
x = 31.63 % P
O:
98 g --------- 100%
64 g --------- x
x = 65.30 % O
``````````````````````````````````````````````````````````````````````````
Ca(OH)2
Ca: 1 x 40 = 40 g/mol
O: 2 x 16 = 32 g/mol
H: 2 x 1 = 2 g/mol
``````````````````````````````
Mm =74 g /mol
Ca:
74 g ----- 100%
40 g ----- x
x = 54.05 % de Ca
O:
74 g ----- 100%
32 g ----- x
x = 43.24 % de O
H:
74 g ----- 100%
2 g ----- x
x = 2.70 % de H
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