Question

porfa ayudame estoy en una practica en la universidad

Answer 1

x^2-{3x+[x(x+1) + 4(x^2-1)- 4x^2]} = 0

x^2-{3x+[x^2+x + 4x^2-4 - 4x^2] } = 0

x^2-{3x+[x^2+x -4 ] } = 0

x^2-{3x+x^2+x -4 } = 0

x^2-{4x+x^2-4 } = 0

x^2 - 4x- x^2 + 4 = 0

- 4x+ 4 = 0

4 = 4x

4/4 = x

1 = x