• Asignatura: Baldor
  • Autor: yansha1
  • hace 9 años

(3x+8)/10-(9x-9)/14=(31x-4)/14+(4x-1)/35

Respuestas

Respuesta dada por: ambarsmith815
8

(3*x+8)/10-((9*x-9)/14) = (31*x-4)/14+(4*x-1)/35 // - (31*x-4)/14+(4*x-1)/35

(3*x+8)/10-((9*x-9)/14)-((31*x-4)/14)-((4*x-1)/35) = 0

(3*x+8)/10+(-1*(9*x-9))/14+(-1*(31*x-4))/14+(-1*(4*x-1))/35 = 0

(14*35*(3*x+8))/(10*14*35)+(-1*10*35*(9*x-9))/(10*14*35)+(-1*10*35*(31*x-4))/(10*14*35)+(-1*10*14*(4*x-1))/(10*14*35) = 0

14*35*(3*x+8)-1*10*35*(9*x-9)-1*10*35*(31*x-4)-1*10*14*(4*x-1) = 0

140-1680*x-10850*x-560*x+1400+7070 = 0

140-12530*x-560*x+8470 = 0

8610-13090*x = 0

(8610-13090*x)/(10*14*35) = 0

(8610-13090*x)/(10*14*35) = 0 // * 10*14*35

8610-13090*x = 0

8610-13090*x = 0 // - 8610

-13090*x = -8610 // : -13090

x = -8610/(-13090)

x = 123/187

x = 123/187
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