Question

AYUDAAAAAAAAAA!!!!!!

sen(α) =




tan(β) =




sec(α) =

Answer 1

Primero hallamos la hipotenusa del triangulo

r² = 392² + 245²

r = √(392² + 245²)

r = 462.2651

sen(α) = 245/462.2651


tan(β) = 392/245


sec(α) = 1/cos(α)


cos(α) = 392/462.2651


sec(α) = 462.2651/392