Question

( )log base 2 de 5 + log base 2 (2x+3)=5

Answer 1

log base 2(5(2x+3))=5
2^(log base 2(5(5x+3)))=2^5
5(2x+3)=32
10x+15=32
10x=32-15
10x=17
x=17/10

Answer 2

Propiedades:

$\item{1)} \ log_b A + log_b B = log_b (A*B) \item{2)} Si log_b N = x \to b^x=N$

En base a estas propiedades, resolvemos:

$log_2 5+log_2 (2x+3) = 5 \ \ log_2(5*(2x+3)) = 5 \ \ 5*(2x+3) = 2^5 \ \ 10x+15 = 32 \ \ 10x = 17 \ \ \boxed{\boxed{x = \frac{17}{10}=1.7}}$


Eso es todo! Saludos! Jeizon1L